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Important Notes The assignment is an individual project, to be finished on one’s own effort. The work must be submitted before 6pm Nov. 7th, 2023 (Tuesday), Beijing Time. This is a firm deadline. No late submissions are accepted. Plagiarism is strictly forbidden, regardless of the role in the process. Notably, ten consecutive lines of identical codes are treated as plagiarism. Depending on the seriousness of the plagiarism, 30% − 100% marks will be deducted. This assignment is supposed to be fi ...

Important Notes: The assignment is an individual project, to be finished on one’s own effort. The work must be submitted before 6pm Oct. 17, 2023 (Tuesday), Beijing Time. This is a firm deadline. No late submissions are accepted. Plagiarism is strictly forbidden, regardless of the role in the process. Notably, ten consecutive lines of identical codes are treated as plagiarism. Depending on the seriousness of the plagiarism, 30%-100% marks will be deducted. This assignment is supposed to be fini ...

本文转自微信公众号"胡萝卜周" 原文链接 国外的软件公司，都偏爱开发一系列不同类型软件，这里面，阿香婆就是其一。 首先听到这个名字，很多人可能还以为是中国公司，但是其实人家是妥妥的德国货，只不过借用了中文词语发音而已，阿香婆的英文名是 Ashampoo。 阿香婆这个公司的软件产品非常丰富，但是可能正因为软件太多的原因，给人一种杂而不精的感觉，知名的软件并不多，实用的就更少了。 今天精选几款小编自认为好用的阿香婆软件，每一款都可以独当一面，说是秒杀同行也毫不夸张！ Ashampoo UnInstaller 在安装软件过程中，软件会在系统盘以及注册表中写入很多文件，但是这里面的文件有一部分即使后续软件卸载也无法清除干净。 为了彻底清理这一类残留，衍生出了很多专业的卸载工具，阿香婆也发布了属于自己的卸载工具——Ashampoo UnInstaller。 Ashampoo UnInstaller 的功能可以总结为深度卸载、记录安装、休眠应用、创建快照。 使用深度卸载功能卸载已经安装的软件不会存在文件残留问题，因为 Ashampoo UnInstaller 会自动深度扫描 ...

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实际效果 引用代码 1<img src="https://api.vvhan.com/api/moyu" alt="摸鱼人日历" />

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开源地址: https://github.com/kuroni/bongocat-osu 全键盘版下载地址：https://dsanying.lanzouw.com/ikt1X00bvkeh

input:backpack.in output:backpack.out Time Limits: 1000 ms Memory Limits: 262144 KB Description Input Output Sample Input 12345678910Sample 1:2 153 25 3Sample 2:3 7071 10069 11 2 Sample Output 12345Sample 1:10Sample 2:140 Data Constraint Code 12345678910111213141516171819202122232425262728293031323334353637383940414243#include<bits/stdc++.h>#define IL inlineusing namespace std;typedef long long LL;const int N=100;const int M=1e6;int n;LL m,w[103];LL f[M+3];IL bool eql(LL w1,LL v1,LL ...